如何借助编程进行GPS定位？

答：CommonsWare
（最佳答案）
网上很多的教程都已经过时了，你可以在我的书中下载相关源码，找到Internet/Weather和Service/WeatherPlus的demo，然后使用LocationManager。或者你可以在我的另一本书中，根据23-Location的教程指引，使用LocationManager。
不过，因为GPS需要花费一段时间才能成功安装，所以目前，你也只能通过Android系统进行定位。否则，你只有通过位置升级，或者利用类似的pattern才能完成这个操作。

答：RDC
我创建了一个简易的应用，来完成GPS的相关定位。
以下是全部源码的URL地址
Get Current Location coordinates , City name - in Android
首先，我们需要在manifest文件中添加许可，

<uses-permission android:name="android.permission.ACCESS_FINE_LOCATION" />  

然后创建如下LocationManager的实例：
1
2
LocationManager locationManager = (LocationManager)
getSystemService(Context.LOCATION_SERVICE);
检查GPS能否正常工作
然后执行LocationListener和Get Coordinates

LocationListener locationListener = new MyLocationListener();  locationManager.requestLocationUpdates(  LocationManager.GPS_PROVIDER, 5000, 10, locationListener);

以下是具体代码样例

/*----------Listener class to get coordinates ------------- */private class MyLocationListener implements LocationListener {    @Override    public void onLocationChanged(Location loc) {        editLocation.setText("");        pb.setVisibility(View.INVISIBLE);        Toast.makeText(                getBaseContext(),                "Location changed: Lat: " + loc.getLatitude() + " Lng: "                    + loc.getLongitude(), Toast.LENGTH_SHORT).show();        String longitude = "Longitude: " + loc.getLongitude();        Log.v(TAG, longitude);        String latitude = "Latitude: " + loc.getLatitude();        Log.v(TAG, latitude);        /*-------to get City-Name from coordinates -------- */        String cityName = null;        Geocoder gcd = new Geocoder(getBaseContext(), Locale.getDefault());        List<Address> addresses;        try {            addresses = gcd.getFromLocation(loc.getLatitude(),                    loc.getLongitude(), 1);            if (addresses.size() > 0)                System.out.println(addresses.get(0).getLocality());            cityName = addresses.get(0).getLocality();        } catch (IOException e) {            e.printStackTrace();        }        String s = longitude + "\n" + latitude + "\n\nMy Current City is: "            + cityName;        editLocation.setText(s);    }    @Override    public void onProviderDisabled(String provider) {}    @Override    public void onProviderEnabled(String provider) {}    @Override    public void onStatusChanged(String provider, int status, Bundle extras) {}}

答：Maxim Shoustin
我的方法与以上几位的回答不同，因为Android自带：
GPS_PROVIDER 和 NETWORK_PROVIDER
你可以两个都注册，然后同时启动GPS_PROVIDER和NETWORK_PROVIDER中的onLocationChanged(Location location)。
然后我们可以从两个结果中择优处理，不难发现，NETWORK PROVIDER的定位结果要比GPS更加精确。
下面来定义Location field:

private Location currentBestLocation = null;

下述的方法可以说是介于GPS和Network中，但还是推荐一试，

/** * @return the last know best location */private Location getLastBestLocation() {    Location locationGPS = mLocationManager.getLastKnownLocation(LocationManager.GPS_PROVIDER);    Location locationNet = mLocationManager.getLastKnownLocation(LocationManager.NETWORK_PROVIDER);    long GPSLocationTime = 0;    if (null != locationGPS) { GPSLocationTime = locationGPS.getTime(); }    long NetLocationTime = 0;    if (null != locationNet) {        NetLocationTime = locationNet.getTime();    }    if ( 0 < GPSLocationTime - NetLocationTime ) {        return locationGPS;    }    else{        return locationNet;    }}

每次，进行新的定位时，都会比较之前的定位结果。

...static final int TWO_MINUTES = 1000 * 60 * 2;...

所以，我在onLocationChanged中添加了一种新的method。

@overridepublic void onLocationChanged(Location location) {    makeUseOfNewLocation(location);    if(currentBestLocation == null){        currentBestLocation = location;    }    ....    }/** * This method modify the last know good location according to the arguments. *  * @param location the possible new location */void makeUseOfNewLocation(Location location) {    if ( isBetterLocation(location, currentBestLocation) ) {        currentBestLocation = location;    }}....    /** Determines whether one Location reading is better than the current Location fix * @param location  The new Location that you want to evaluate * @param currentBestLocation  The current Location fix, to which you want to compare the new one */protected boolean isBetterLocation(Location location, Location currentBestLocation) {    if (currentBestLocation == null) {        // A new location is always better than no location        return true;    }    // Check whether the new location fix is newer or older    long timeDelta = location.getTime() - currentBestLocation.getTime();    boolean isSignificantlyNewer = timeDelta > TWO_MINUTES;    boolean isSignificantlyOlder = timeDelta < -TWO_MINUTES;    boolean isNewer = timeDelta > 0;    // If it's been more than two minutes since the current location, use the new location    // because the user has likely moved    if (isSignificantlyNewer) {        return true;        // If the new location is more than two minutes older, it must be worse    } else if (isSignificantlyOlder) {        return false;    }    // Check whether the new location fix is more or less accurate    int accuracyDelta = (int) (location.getAccuracy() - currentBestLocation.getAccuracy());    boolean isLessAccurate = accuracyDelta > 0;    boolean isMoreAccurate = accuracyDelta < 0;    boolean isSignificantlyLessAccurate = accuracyDelta > 200;    // Check if the old and new location are from the same provider    boolean isFromSameProvider = isSameProvider(location.getProvider(),            currentBestLocation.getProvider());    // Determine location quality using a combination of timeliness and accuracy    if (isMoreAccurate) {        return true;    } else if (isNewer && !isLessAccurate) {        return true;    } else if (isNewer && !isSignificantlyLessAccurate && isFromSameProvider) {        return true;    }    return false;}/** Checks whether two providers are the same */private boolean isSameProvider(String provider1, String provider2) {    if (provider1 == null) {        return provider2 == null;    }    return provider1.equals(provider2);}....