char* askForAString(void){ char temp[16] = ""; //这里是第81行 //scanf("%s", temp); //fflush(stdin); return temp;}char password[16] = "evlos";char inputpsw[16];inputpsw = askForAString(); //这里是第100行if (strcmp(password, inputpsw) == 0){ printf("Allowed!");}projectv0.cpp: In function ‘char* askForAString()’:
projectv0.cpp:81: warning: address of local variable ‘temp’ returned
projectv0.cpp:100: error: incompatible types in assignment of ‘char*’ to ‘char [16]’
请问如何修改才能让程序正常运行？
再请问 “warning: address of local variable ‘temp’ returned” 这个错误是怎么产生应该如何避免呢？
谢谢啦 =w=
解决方案
#include <iostream>#include <list>#include <string>std::string askForAString(void){ std::string temp; getline(std::cin, temp); return temp;}int main(int argc, char* argv){ std::string password("evlos"); if ( 0 == password.compare(askForAString()) ) { std::cout << "OK" << std::endl; } system("pause");}