async function a() { let a1 = await new Promise(function(resolve, reject) { var num = 5; return num; }); let a2 = await new Promise(function(resolve,reject){ //我想在这里拿到a1的返回值 }); let a3 = await a2() //我想拿到a2的返回值}解决方案
async function a() { let a1 = await new Promise(function(resolve, reject) { const num = 5; resolve(num) }); let a2 = await new Promise(function(resolve,reject){ //我想在这里拿到a1的返回值 console.log(a1) // 5 resolve(a1) }); let a3 = await a2 //我想拿到a2的返回值 console.log(a3) // 5}a()这样就可以了啊，希望能帮到你，Promise需要把结果放在resolve里面 而不是 return，
另外你都用async await 就不要用var了吧，箭头函数也可以搞起来 代码可以简洁不少